\(\int \frac {(12-3 e^2 x^2)^{3/2}}{(2+e x)^{5/2}} \, dx\) [906]

Optimal result

Integrand size = 24, antiderivative size = 66 \[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=\frac {24 \sqrt {3} \sqrt {2-e x}}{e}+\frac {2 \sqrt {3} (2-e x)^{3/2}}{e}-\frac {48 \sqrt {3} \text {arctanh}\left (\frac {1}{2} \sqrt {2-e x}\right )}{e} \]

[Out]

2*(-e*x+2)^(3/2)/e*3^(1/2)-48*arctanh(1/2*(-e*x+2)^(1/2))*3^(1/2)/e+24*3^(1/2)*(-e*x+2)^(1/2)/e

Rubi [A] (verified)

Time = 0.02 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {641, 52, 65, 212} \[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=-\frac {48 \sqrt {3} \text {arctanh}\left (\frac {1}{2} \sqrt {2-e x}\right )}{e}+\frac {2 \sqrt {3} (2-e x)^{3/2}}{e}+\frac {24 \sqrt {3} \sqrt {2-e x}}{e} \]

[In]

Int[(12 - 3*e^2*x^2)^(3/2)/(2 + e*x)^(5/2),x]

[Out]

(24*Sqrt[3]*Sqrt[2 - e*x])/e + (2*Sqrt[3]*(2 - e*x)^(3/2))/e - (48*Sqrt[3]*ArcTanh[Sqrt[2 - e*x]/2])/e

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 641

Int[((d_) + (e_.)*(x_))^(m_.)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)^(m + p)*(a/d + (c/e)*x)^
p, x] /; FreeQ[{a, c, d, e, m, p}, x] && EqQ[c*d^2 + a*e^2, 0] && (IntegerQ[p] || (GtQ[a, 0] && GtQ[d, 0] && I
ntegerQ[m + p]))

Rubi steps \begin{align*} \text {integral}& = \int \frac {(6-3 e x)^{3/2}}{2+e x} \, dx \\ & = \frac {2 \sqrt {3} (2-e x)^{3/2}}{e}+12 \int \frac {\sqrt {6-3 e x}}{2+e x} \, dx \\ & = \frac {24 \sqrt {3} \sqrt {2-e x}}{e}+\frac {2 \sqrt {3} (2-e x)^{3/2}}{e}+144 \int \frac {1}{\sqrt {6-3 e x} (2+e x)} \, dx \\ & = \frac {24 \sqrt {3} \sqrt {2-e x}}{e}+\frac {2 \sqrt {3} (2-e x)^{3/2}}{e}-\frac {96 \text {Subst}\left (\int \frac {1}{4-\frac {x^2}{3}} \, dx,x,\sqrt {6-3 e x}\right )}{e} \\ & = \frac {24 \sqrt {3} \sqrt {2-e x}}{e}+\frac {2 \sqrt {3} (2-e x)^{3/2}}{e}-\frac {48 \sqrt {3} \tanh ^{-1}\left (\frac {1}{2} \sqrt {2-e x}\right )}{e} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.46 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.17 \[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=-\frac {2 \sqrt {3} \left ((-14+e x) \sqrt {4-e^2 x^2}+24 \sqrt {2+e x} \text {arctanh}\left (\frac {2 \sqrt {2+e x}}{\sqrt {4-e^2 x^2}}\right )\right )}{e \sqrt {2+e x}} \]

[In]

Integrate[(12 - 3*e^2*x^2)^(3/2)/(2 + e*x)^(5/2),x]

[Out]

(-2*Sqrt[3]*((-14 + e*x)*Sqrt[4 - e^2*x^2] + 24*Sqrt[2 + e*x]*ArcTanh[(2*Sqrt[2 + e*x])/Sqrt[4 - e^2*x^2]]))/(
e*Sqrt[2 + e*x])

Maple [A] (verified)

Time = 2.27 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.17

method	result	size
default	\(-\frac {2 \sqrt {-x^{2} e^{2}+4}\, \left (e x \sqrt {-3 e x +6}+24 \sqrt {3}\, \operatorname {arctanh}\left (\frac {\sqrt {-3 e x +6}\, \sqrt {3}}{6}\right )-14 \sqrt {-3 e x +6}\right ) \sqrt {3}}{\sqrt {e x +2}\, \sqrt {-3 e x +6}\, e}\)	\(77\)
risch	\(\frac {6 \left (e x -14\right ) \left (e x -2\right ) \sqrt {\frac {-3 x^{2} e^{2}+12}{e x +2}}\, \sqrt {e x +2}}{e \sqrt {-3 e x +6}\, \sqrt {-3 x^{2} e^{2}+12}}-\frac {48 \sqrt {3}\, \operatorname {arctanh}\left (\frac {\sqrt {-3 e x +6}\, \sqrt {3}}{6}\right ) \sqrt {\frac {-3 x^{2} e^{2}+12}{e x +2}}\, \sqrt {e x +2}}{e \sqrt {-3 x^{2} e^{2}+12}}\)	\(125\)

[In]

int((-3*e^2*x^2+12)^(3/2)/(e*x+2)^(5/2),x,method=_RETURNVERBOSE)

[Out]

-2*(-e^2*x^2+4)^(1/2)*(e*x*(-3*e*x+6)^(1/2)+24*3^(1/2)*arctanh(1/6*(-3*e*x+6)^(1/2)*3^(1/2))-14*(-3*e*x+6)^(1/
2))*3^(1/2)/(e*x+2)^(1/2)/(-3*e*x+6)^(1/2)/e

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 106 vs. \(2 (52) = 104\).

Time = 0.29 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.61 \[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=\frac {2 \, {\left (12 \, \sqrt {3} {\left (e x + 2\right )} \log \left (-\frac {3 \, e^{2} x^{2} - 12 \, e x + 4 \, \sqrt {3} \sqrt {-3 \, e^{2} x^{2} + 12} \sqrt {e x + 2} - 36}{e^{2} x^{2} + 4 \, e x + 4}\right ) - \sqrt {-3 \, e^{2} x^{2} + 12} \sqrt {e x + 2} {\left (e x - 14\right )}\right )}}{e^{2} x + 2 \, e} \]

[In]

integrate((-3*e^2*x^2+12)^(3/2)/(e*x+2)^(5/2),x, algorithm="fricas")

[Out]

2*(12*sqrt(3)*(e*x + 2)*log(-(3*e^2*x^2 - 12*e*x + 4*sqrt(3)*sqrt(-3*e^2*x^2 + 12)*sqrt(e*x + 2) - 36)/(e^2*x^
2 + 4*e*x + 4)) - sqrt(-3*e^2*x^2 + 12)*sqrt(e*x + 2)*(e*x - 14))/(e^2*x + 2*e)

Sympy [F]

\[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=3 \sqrt {3} \left (\int \frac {4 \sqrt {- e^{2} x^{2} + 4}}{e^{2} x^{2} \sqrt {e x + 2} + 4 e x \sqrt {e x + 2} + 4 \sqrt {e x + 2}}\, dx + \int \left (- \frac {e^{2} x^{2} \sqrt {- e^{2} x^{2} + 4}}{e^{2} x^{2} \sqrt {e x + 2} + 4 e x \sqrt {e x + 2} + 4 \sqrt {e x + 2}}\right )\, dx\right ) \]

[In]

integrate((-3*e**2*x**2+12)**(3/2)/(e*x+2)**(5/2),x)

[Out]

3*sqrt(3)*(Integral(4*sqrt(-e**2*x**2 + 4)/(e**2*x**2*sqrt(e*x + 2) + 4*e*x*sqrt(e*x + 2) + 4*sqrt(e*x + 2)),
x) + Integral(-e**2*x**2*sqrt(-e**2*x**2 + 4)/(e**2*x**2*sqrt(e*x + 2) + 4*e*x*sqrt(e*x + 2) + 4*sqrt(e*x + 2)
), x))

Maxima [F]

\[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=\int { \frac {{\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {3}{2}}}{{\left (e x + 2\right )}^{\frac {5}{2}}} \,d x } \]

[In]

integrate((-3*e^2*x^2+12)^(3/2)/(e*x+2)^(5/2),x, algorithm="maxima")

[Out]

integrate((-3*e^2*x^2 + 12)^(3/2)/(e*x + 2)^(5/2), x)

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.83 \[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=\frac {2 \, \sqrt {3} {\left ({\left (-e x + 2\right )}^{\frac {3}{2}} + 12 \, \sqrt {-e x + 2} - 12 \, \log \left (\sqrt {-e x + 2} + 2\right ) + 12 \, \log \left (-\sqrt {-e x + 2} + 2\right )\right )}}{e} \]

[In]

integrate((-3*e^2*x^2+12)^(3/2)/(e*x+2)^(5/2),x, algorithm="giac")

[Out]

2*sqrt(3)*((-e*x + 2)^(3/2) + 12*sqrt(-e*x + 2) - 12*log(sqrt(-e*x + 2) + 2) + 12*log(-sqrt(-e*x + 2) + 2))/e

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (12-3 e^2 x^2\right )^{3/2}}{(2+e x)^{5/2}} \, dx=\int \frac {{\left (12-3\,e^2\,x^2\right )}^{3/2}}{{\left (e\,x+2\right )}^{5/2}} \,d x \]

[In]

int((12 - 3*e^2*x^2)^(3/2)/(e*x + 2)^(5/2),x)

[Out]

int((12 - 3*e^2*x^2)^(3/2)/(e*x + 2)^(5/2), x)